A yellow precipitate forms when silver nitrate is added. Which ion is present?

A yellow precipitate forms when silver nitrate is added. Which ion is present?

• A. Iodide (I-)
• B. Chloride (Cl-)
• C. Nitrate (NO3-)
• D. Sulfate (SO4 2-)

Answer: (A)

When a solution containing halide ions is treated with silver Nitrate, silver halides form as precipitates and their colors reveal which halide is present. A yellow solid forms specifically from silver iodide, because AgI is insoluble and yellow. In contrast, silver chloride gives a white precipitate, and silver sulfate also yields a white precipitate, while nitrates generally stay in solution and don’t form a visible precipitate. So the appearance of a yellow precipitate points to iodide ions being present.

When a solution containing halide ions is treated with silver Nitrate, silver halides form as precipitates and their colors reveal which halide is present. A yellow solid forms specifically from silver iodide, because AgI is insoluble and yellow. In contrast, silver chloride gives a white precipitate, and silver sulfate also yields a white precipitate, while nitrates generally stay in solution and don’t form a visible precipitate. So the appearance of a yellow precipitate points to iodide ions being present.